Optimal. Leaf size=80 \[ \frac{1}{2} x \left (a^2 B+4 a b C+2 b^2 B\right )+\frac{a^2 B \sin (c+d x) \cos (c+d x)}{2 d}+\frac{a (a C+2 b B) \sin (c+d x)}{d}+\frac{b^2 C \tanh ^{-1}(\sin (c+d x))}{d} \]
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Rubi [A] time = 0.251598, antiderivative size = 80, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.15, Rules used = {4072, 4024, 4047, 8, 4045, 3770} \[ \frac{1}{2} x \left (a^2 B+4 a b C+2 b^2 B\right )+\frac{a^2 B \sin (c+d x) \cos (c+d x)}{2 d}+\frac{a (a C+2 b B) \sin (c+d x)}{d}+\frac{b^2 C \tanh ^{-1}(\sin (c+d x))}{d} \]
Antiderivative was successfully verified.
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Rule 4072
Rule 4024
Rule 4047
Rule 8
Rule 4045
Rule 3770
Rubi steps
\begin{align*} \int \cos ^3(c+d x) (a+b \sec (c+d x))^2 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\int \cos ^2(c+d x) (a+b \sec (c+d x))^2 (B+C \sec (c+d x)) \, dx\\ &=\frac{a^2 B \cos (c+d x) \sin (c+d x)}{2 d}-\frac{1}{2} \int \cos (c+d x) \left (-2 a (2 b B+a C)+\left (\left (-a^2-2 b^2\right ) B-4 a b C\right ) \sec (c+d x)-2 b^2 C \sec ^2(c+d x)\right ) \, dx\\ &=\frac{a^2 B \cos (c+d x) \sin (c+d x)}{2 d}-\frac{1}{2} \int \cos (c+d x) \left (-2 a (2 b B+a C)-2 b^2 C \sec ^2(c+d x)\right ) \, dx-\frac{1}{2} \left (-a^2 B-2 b^2 B-4 a b C\right ) \int 1 \, dx\\ &=\frac{1}{2} \left (a^2 B+2 b^2 B+4 a b C\right ) x+\frac{a (2 b B+a C) \sin (c+d x)}{d}+\frac{a^2 B \cos (c+d x) \sin (c+d x)}{2 d}+\left (b^2 C\right ) \int \sec (c+d x) \, dx\\ &=\frac{1}{2} \left (a^2 B+2 b^2 B+4 a b C\right ) x+\frac{b^2 C \tanh ^{-1}(\sin (c+d x))}{d}+\frac{a (2 b B+a C) \sin (c+d x)}{d}+\frac{a^2 B \cos (c+d x) \sin (c+d x)}{2 d}\\ \end{align*}
Mathematica [A] time = 0.221225, size = 120, normalized size = 1.5 \[ \frac{2 (c+d x) \left (a^2 B+4 a b C+2 b^2 B\right )+a^2 B \sin (2 (c+d x))+4 a (a C+2 b B) \sin (c+d x)-4 b^2 C \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+4 b^2 C \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )}{4 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.058, size = 120, normalized size = 1.5 \begin{align*}{\frac{B{a}^{2}\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2\,d}}+{\frac{{a}^{2}Bx}{2}}+{\frac{B{a}^{2}c}{2\,d}}+{\frac{{a}^{2}C\sin \left ( dx+c \right ) }{d}}+2\,{\frac{Bab\sin \left ( dx+c \right ) }{d}}+2\,abCx+2\,{\frac{Cabc}{d}}+B{b}^{2}x+{\frac{B{b}^{2}c}{d}}+{\frac{{b}^{2}C\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.959688, size = 134, normalized size = 1.68 \begin{align*} \frac{{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} B a^{2} + 8 \,{\left (d x + c\right )} C a b + 4 \,{\left (d x + c\right )} B b^{2} + 2 \, C b^{2}{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 4 \, C a^{2} \sin \left (d x + c\right ) + 8 \, B a b \sin \left (d x + c\right )}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.522297, size = 213, normalized size = 2.66 \begin{align*} \frac{C b^{2} \log \left (\sin \left (d x + c\right ) + 1\right ) - C b^{2} \log \left (-\sin \left (d x + c\right ) + 1\right ) +{\left (B a^{2} + 4 \, C a b + 2 \, B b^{2}\right )} d x +{\left (B a^{2} \cos \left (d x + c\right ) + 2 \, C a^{2} + 4 \, B a b\right )} \sin \left (d x + c\right )}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.21033, size = 240, normalized size = 3. \begin{align*} \frac{2 \, C b^{2} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) - 2 \, C b^{2} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) +{\left (B a^{2} + 4 \, C a b + 2 \, B b^{2}\right )}{\left (d x + c\right )} - \frac{2 \,{\left (B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 2 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 4 \, B a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 2 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 4 \, B a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{2}}}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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